किस व्यंजक को \(x\neq0\) पर सरल करने के बाद बहुपद \(x^2+1\) मिलेगा?
Which expression gives the polynomial \(x^2+1\) after simplification for \(x\neq0\)?
Explanation opens after your attempt
Correct Answer
A. \(\frac{x^3+x}{x}\)
Concept
\(\frac{x^3+x}{x}=x^2+1\). In the simplified form, the powers are (2) and (0), so it is a polynomial.
Why this answer is correct
The correct answer is A. \(\frac{x^3+x}{x}\). \(\frac{x^3+x}{x}=x^2+1\). In the simplified form, the powers are (2) and (0), so it is a polynomial.
Exam Tip
\(\frac{x^3+x}{x}=x^2+1\) है। सरल रूप में घातें (2) और (0) हैं, इसलिए यह बहुपद है।
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