कौन सा मानक वर्गमूल सर्पिल में सीधा पहला कर्ण नहीं हो सकता?

Which cannot be the direct first hypotenuse in a standard square root spiral?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

C. \(\sqrt{4}\)

Step 1

Concept

The first hypotenuse is formed from (1) and (1), giving \(\sqrt{2}\). \(\sqrt{4}\) appears in a later step, not as the first hypotenuse.

Step 2

Why this answer is correct

The correct answer is C. \(\sqrt{4}\). The first hypotenuse is formed from (1) and (1), giving \(\sqrt{2}\). \(\sqrt{4}\) appears in a later step, not as the first hypotenuse.

Step 3

Exam Tip

पहला कर्ण (1) और (1) से बनकर \(\sqrt{2}\) होता है। \(\sqrt{4}\) बाद के चरण में मिलता है, पहले कर्ण के रूप में नहीं।

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Mathematics Answer, Explanation and Revision Hints

कौन सा मानक वर्गमूल सर्पिल में सीधा पहला कर्ण नहीं हो सकता? / Which cannot be the direct first hypotenuse in a standard square root spiral?

Correct Answer: C. \(\sqrt{4}\). Explanation: पहला कर्ण (1) और (1) से बनकर \(\sqrt{2}\) होता है। \(\sqrt{4}\) बाद के चरण में मिलता है, पहले कर्ण के रूप में नहीं। / The first hypotenuse is formed from (1) and (1), giving \(\sqrt{2}\). \(\sqrt{4}\) appears in a later step, not as the first hypotenuse.

Which concept should I revise for this Mathematics MCQ?

The first hypotenuse is formed from (1) and (1), giving \(\sqrt{2}\). \(\sqrt{4}\) appears in a later step, not as the first hypotenuse.

What exam hint can help solve this Mathematics question?

पहला कर्ण (1) और (1) से बनकर \(\sqrt{2}\) होता है। \(\sqrt{4}\) बाद के चरण में मिलता है, पहले कर्ण के रूप में नहीं।