वर्गमूल सर्पिल में \(\sqrt{28}\) किस प्रकार की संख्या है और किस अंतराल में है?

What type of number is \(\sqrt{28}\) in a square root spiral and in which interval does it lie?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. अपरिमेय संख्या और (5) तथा (6) के बीचIrrational number and between (5) and (6)

Step 1

Concept

(28) is not a perfect square and \(5^2<28<6^2\). Therefore \(\sqrt{28}\) is irrational and lies between (5) and (6).

Step 2

Why this answer is correct

The correct answer is B. अपरिमेय संख्या और (5) तथा (6) के बीच / Irrational number and between (5) and (6). (28) is not a perfect square and \(5^2<28<6^2\). Therefore \(\sqrt{28}\) is irrational and lies between (5) and (6).

Step 3

Exam Tip

(28) पूर्ण वर्ग नहीं है और \(5^2<28<6^2\) है। इसलिए \(\sqrt{28}\) अपरिमेय है और (5) तथा (6) के बीच है।

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वर्गमूल सर्पिल में \(\sqrt{28}\) किस प्रकार की संख्या है और किस अंतराल में है? / What type of number is \(\sqrt{28}\) in a square root spiral and in which interval does it lie?

Correct Answer: B. अपरिमेय संख्या और (5) तथा (6) के बीच / Irrational number and between (5) and (6). Explanation: (28) पूर्ण वर्ग नहीं है और \(5^2<28<6^2\) है। इसलिए \(\sqrt{28}\) अपरिमेय है और (5) तथा (6) के बीच है। / (28) is not a perfect square and \(5^2<28<6^2\). Therefore \(\sqrt{28}\) is irrational and lies between (5) and (6).

Which concept should I revise for this Mathematics MCQ?

(28) is not a perfect square and \(5^2<28<6^2\). Therefore \(\sqrt{28}\) is irrational and lies between (5) and (6).

What exam hint can help solve this Mathematics question?

(28) पूर्ण वर्ग नहीं है और \(5^2<28<6^2\) है। इसलिए \(\sqrt{28}\) अपरिमेय है और (5) तथा (6) के बीच है।