(\(\sqrt{19}+4\)2-\(\sqrt{19}-4\)2) का मान क्या है?

What is the value of (\(\sqrt{19}+4\)2-\(\sqrt{19}-4\)2)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(16\sqrt{19}\)

Step 1

Concept

Use ((a+b)2-(a-b)2=4ab). Here \(a=\sqrt{19}\) and (b=4), so the value is \(16\sqrt{19}\).

Step 2

Why this answer is correct

The correct answer is A. \(16\sqrt{19}\). Use ((a+b)2-(a-b)2=4ab). Here \(a=\sqrt{19}\) and (b=4), so the value is \(16\sqrt{19}\).

Step 3

Exam Tip

पहचान ((a+b)2-(a-b)2=4ab) लगाएं। यहाँ \(a=\sqrt{19}\) और (b=4), इसलिए मान \(16\sqrt{19}\) है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

(\(\sqrt{19}+4\)2-\(\sqrt{19}-4\)2) का मान क्या है? / What is the value of (\(\sqrt{19}+4\)2-\(\sqrt{19}-4\)2)?

Correct Answer: A. \(16\sqrt{19}\). Explanation: पहचान ((a+b)2-(a-b)2=4ab) लगाएं। यहाँ \(a=\sqrt{19}\) और (b=4), इसलिए मान \(16\sqrt{19}\) है। / Use ((a+b)2-(a-b)2=4ab). Here \(a=\sqrt{19}\) and (b=4), so the value is \(16\sqrt{19}\).

Which concept should I revise for this Mathematics MCQ?

Use ((a+b)2-(a-b)2=4ab). Here \(a=\sqrt{19}\) and (b=4), so the value is \(16\sqrt{19}\).

What exam hint can help solve this Mathematics question?

पहचान ((a+b)2-(a-b)2=4ab) लगाएं। यहाँ \(a=\sqrt{19}\) और (b=4), इसलिए मान \(16\sqrt{19}\) है।