\(\frac{1}{\sqrt{2}+1}+\frac{1}{\sqrt{2}-1}\) का मान क्या है?

What is the value of \(\frac{1}{\sqrt{2}+1}+\frac{1}{\sqrt{2}-1}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

B. \(2\sqrt{2}\)

Step 1

Concept

The first term becomes \(\sqrt{2}-1\) and the second becomes \(\sqrt{2}+1\). Their sum is \(2\sqrt{2}\).

Step 2

Why this answer is correct

The correct answer is B. \(2\sqrt{2}\). The first term becomes \(\sqrt{2}-1\) and the second becomes \(\sqrt{2}+1\). Their sum is \(2\sqrt{2}\).

Step 3

Exam Tip

पहला पद \(\sqrt{2}-1\) और दूसरा \(\sqrt{2}+1\) बनता है। योग \(2\sqrt{2}\) है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

\(\frac{1}{\sqrt{2}+1}+\frac{1}{\sqrt{2}-1}\) का मान क्या है? / What is the value of \(\frac{1}{\sqrt{2}+1}+\frac{1}{\sqrt{2}-1}\)?

Correct Answer: B. \(2\sqrt{2}\). Explanation: पहला पद \(\sqrt{2}-1\) और दूसरा \(\sqrt{2}+1\) बनता है। योग \(2\sqrt{2}\) है। / The first term becomes \(\sqrt{2}-1\) and the second becomes \(\sqrt{2}+1\). Their sum is \(2\sqrt{2}\).

Which concept should I revise for this Mathematics MCQ?

The first term becomes \(\sqrt{2}-1\) and the second becomes \(\sqrt{2}+1\). Their sum is \(2\sqrt{2}\).

What exam hint can help solve this Mathematics question?

पहला पद \(\sqrt{2}-1\) और दूसरा \(\sqrt{2}+1\) बनता है। योग \(2\sqrt{2}\) है।