\(\frac{1}{\sqrt{2}+1}+\frac{1}{\sqrt{2}-1}\) का मान क्या है?
What is the value of \(\frac{1}{\sqrt{2}+1}+\frac{1}{\sqrt{2}-1}\)?
Explanation opens after your attempt
B. \(2\sqrt{2}\)
Concept
The first term becomes \(\sqrt{2}-1\) and the second becomes \(\sqrt{2}+1\). Their sum is \(2\sqrt{2}\).
Why this answer is correct
The correct answer is B. \(2\sqrt{2}\). The first term becomes \(\sqrt{2}-1\) and the second becomes \(\sqrt{2}+1\). Their sum is \(2\sqrt{2}\).
Exam Tip
पहला पद \(\sqrt{2}-1\) और दूसरा \(\sqrt{2}+1\) बनता है। योग \(2\sqrt{2}\) है।
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