गुणोत्तर श्रेणी \(3,9,27,81,\ldots\) के पहले (6) पदों का योग क्या है?

What is the sum of the first (6) terms of the geometric progression \(3,9,27,81,\ldots\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

B. (1093)

Step 1

Concept

(S_6=\frac{3\(3^6-1\)}{3-1}=1092). In exams, you can also verify the sum by direct addition.

Step 2

Why this answer is correct

The correct answer is B. (1093). (S_6=\frac{3\(3^6-1\)}{3-1}=1092). In exams, you can also verify the sum by direct addition.

Step 3

Exam Tip

(S_6=\frac{3\(3^6-1\)}{3-1}=1092) नहीं, सही गणना (3+9+27+81+243+729=1092) है। परीक्षा में योग को सीधे जोड़कर भी जाँचें।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

गुणोत्तर श्रेणी \(3,9,27,81,\ldots\) के पहले (6) पदों का योग क्या है? / What is the sum of the first (6) terms of the geometric progression \(3,9,27,81,\ldots\)?

Correct Answer: B. (1093). Explanation: (S_6=\frac{3\(3^6-1\)}{3-1}=1092) नहीं, सही गणना (3+9+27+81+243+729=1092) है। परीक्षा में योग को सीधे जोड़कर भी जाँचें। / (S_6=\frac{3\(3^6-1\)}{3-1}=1092). In exams, you can also verify the sum by direct addition.

Which concept should I revise for this Mathematics MCQ?

(S_6=\frac{3\(3^6-1\)}{3-1}=1092). In exams, you can also verify the sum by direct addition.

What exam hint can help solve this Mathematics question?

(S_6=\frac{3\(3^6-1\)}{3-1}=1092) नहीं, सही गणना (3+9+27+81+243+729=1092) है। परीक्षा में योग को सीधे जोड़कर भी जाँचें।