गुणोत्तर श्रेणी \(3,9,27,81,\ldots\) के पहले (6) पदों का योग क्या है?
What is the sum of the first (6) terms of the geometric progression \(3,9,27,81,\ldots\)?
Explanation opens after your attempt
B. (1093)
Concept
(S_6=\frac{3\(3^6-1\)}{3-1}=1092). In exams, you can also verify the sum by direct addition.
Why this answer is correct
The correct answer is B. (1093). (S_6=\frac{3\(3^6-1\)}{3-1}=1092). In exams, you can also verify the sum by direct addition.
Exam Tip
(S_6=\frac{3\(3^6-1\)}{3-1}=1092) नहीं, सही गणना (3+9+27+81+243+729=1092) है। परीक्षा में योग को सीधे जोड़कर भी जाँचें।
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