What is the (n)th term of the sequence (\frac{9}{5},\frac{18}{5},\frac{27}{5},\frac{36}{5},\ldots)?
Answer and explanation
Correct answer: (\frac{9n}{5})
Each term increases by (\frac{9}{5}), so (a_n=\frac{9n}{5}). In fractions with a common denominator, observe the numerator pattern.
Frequently asked questions
What is the correct answer to this question?
(\frac{9n}{5})
Why is this the correct answer?
Each term increases by (\frac{9}{5}), so (a_n=\frac{9n}{5}). In fractions with a common denominator, observe the numerator pattern.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: nth term.
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