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What is the (n)th term of the sequence (6,24,96,384,\ldots)?

Answer and explanation

Correct answer: (6\cdot4^{n-1})

The correct answer is option A: \\(a_n=6\cdot4^{n-1}\\). This is a geometric sequence because each term is obtained by multiplying the previous term by 4: \\(24/6=4\\), \\(96/24=4\\), and \\(384/96=4\\). For a geometric sequence, the nth term is \\(a_n=ar^{n-1}\\), where \\(a\\) is the first term and \\(r\\) is the common ratio. Here \\(a=6\\) and \\(r=4\\), so \\(a_n=6\cdot4^{n-1}\\). Option A gives the first term when \\(n=1\\): \\(6\cdot4^0=6\\), so it works. Option B gives 4 when \\(n=1\\), not 6. Option C gives \\(24\\) for \\(n=1\\), so its exponent is one step too large. Option D also gives 24 for the first term, not 6. Memory cue: first term stays outside, and the exponent is one less than the term number.

Related tags

SequencesProgressionsNth-TermGeometric

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