Update

Muft Shiksha™ एक 100% Free Education Portal है 🇮🇳, जिसका उद्देश्य Class 9–12 के हर विद्यार्थी तक High-Quality Education को पूरी तरह मुफ्त पहुँचाना है। 🇮🇳 हम मानते हैं कि अच्छी शिक्षा किसी student की आर्थिक स्थिति पर निर्भर नहीं होनी चाहिए। 🇮🇳 हर विद्यार्थी को वही Quality Study Material, MCQs, Quizzes, Exam Preparation, Concept-Based Learning और Bilingual Support मिलना चाहिए, जो आमतौर पर महंगी Coaching या Premium Platforms में मिलता है। Muft Shiksha™ 🇮🇳 इसी सोच के साथ बनाया गया है

Subjects
0 reads0 ratings0 helpful

If aₙ = n³ − n, what will be the value of a₇ − a₅?

Advertisement

Answer and explanation

Correct answer: 216

The governing concept is evaluation of an explicit, or general, rule for a sequence. Substitute n = 7 and n = 5 separately into aₙ = n³ − n. We get a₇ = 7³ − 7 = 343 − 7 = 336, and a₅ = 5³ − 5 = 125 − 5 = 120. Therefore, a₇ − a₅ = 336 − 120 = 216, so option B is correct. A useful algebraic check is 7³ − 7 − (5³ − 5) = 343 − 7 − 125 + 5 = 216. The other options arise from an incorrect cube, forgetting the subtraction of n, or subtracting the terms incorrectly. Evaluating each term carefully avoids those errors.

Related tags

SequencesExplicit-RuleNth-TermCubic-ExpressionNth TermSequences And ProgressionsMathematicsClass 9 Mcq

Frequently asked questions

What is the correct answer to this question?

216

Why is this the correct answer?

The governing concept is evaluation of an explicit, or general, rule for a sequence. Substitute n = 7 and n = 5 separately into aₙ = n³ − n. We get a₇ = 7³ − 7 = 343 − 7 = 336, and a₅ = 5³ − 5 = 125 − 5 = 120. Therefore, a₇ − a₅ = 336 − 120 = 216, so option B is correct. A useful algebraic check is 7³ − 7 − (5³ − 5) = 343 − 7 − 125 + 5 = 216. The other options arise from an incorrect cube, forgetting the subtraction of n, or subtracting the terms incorrectly. Evaluating each term carefully avoids those errors.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: nth term.

Was this question useful?

No ratings yetWrite a review / Rate this question

Student Reviews

No published reviews yet.

Advertisement