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If a_n = 4n² − 1, which term is 575?

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Answer and explanation

Correct answer: 12th

The governing concept is finding a term position from an nth-term formula. We seek n such that 4n² − 1 = 575. Adding 1 to both sides gives 4n² = 576. Dividing by 4 gives n² = 144, so the positive term position is n = 12; a sequence position cannot be negative. Direct substitution confirms this: a_12 = 4(12²) − 1 = 4 × 144 − 1 = 576 − 1 = 575. Therefore option C is correct. The nearby choices give a_11 = 483 and a_13 = 675, so they cannot produce 575. The negative square root is rejected because term numbers are positive integers.

Related tags

SequencesNth-TermQuadratic-RuleTerm-PositionNth TermSequences And ProgressionsMathematicsClass 9 Mcq

Frequently asked questions

What is the correct answer to this question?

12th

Why is this the correct answer?

The governing concept is finding a term position from an nth-term formula. We seek n such that 4n² − 1 = 575. Adding 1 to both sides gives 4n² = 576. Dividing by 4 gives n² = 144, so the positive term position is n = 12; a sequence position cannot be negative. Direct substitution confirms this: a_12 = 4(12²) − 1 = 4 × 144 − 1 = 576 − 1 = 575. Therefore option C is correct. The nearby choices give a_11 = 483 and a_13 = 675, so they cannot produce 575. The negative square root is rejected because term numbers are positive integers.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: nth term.

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