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What is the (n)th term of the sequence (16,8,4,2,1,\ldots)?श्रेणी (16,8,4,2,1,\ldots) का (n)वां पद क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(16\left(\frac{1}{2}\right)^{n-1}\)\(16\left(\frac{1}{2}\right)^{n-1}\)
Each term is half of the previous one, so \(a_n=16\left(\frac{1}{2}\right)^{n-1}\). Keep the first term fixed and use exponent (n-1).हर पद पिछले का आधा है इसलिए \(a_n=16\left(\frac{1}{2}\right)^{n-1}\)। पहले पद को सुरक्षित रखकर (n-1) घात लगाएं।
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