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What is the (n)th term of the sequence (12,28,50,78,112,\ldots)?श्रेणी (12,28,50,78,112,\ldots) का (n)वां पद क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (3n^2+7n+2)(3n^2+7n+2)
The second differences are (6), and (3n^2+7n+2) gives the starting terms. In a quadratic rule, half of the second difference is the coefficient of (n^2).दूसरे अंतर (6) हैं और (3n^2+7n+2) शुरुआती पद देता है। द्विघात नियम में दूसरे अंतर का आधा (n^2) का गुणांक होता है।
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