वर्गमूल सर्पिल में (OA=1) को \(\sqrt{1}\) मानने का मुख्य लाभ क्या है?

What is the main advantage of treating (OA=1) as \(\sqrt{1}\) in a square root spiral?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

A. क्रम \(\sqrt{1},\sqrt{2},\sqrt{3}\) स्पष्ट हो जाता हैThe order \(\sqrt{1},\sqrt{2},\sqrt{3}\) becomes clear

Step 1

Concept

Taking \(1=\sqrt{1}\) makes the whole sequence clear. Then the inner number increases by (1) at each step.

Step 2

Why this answer is correct

The correct answer is A. क्रम \(\sqrt{1},\sqrt{2},\sqrt{3}\) स्पष्ट हो जाता है / The order \(\sqrt{1},\sqrt{2},\sqrt{3}\) becomes clear. Taking \(1=\sqrt{1}\) makes the whole sequence clear. Then the inner number increases by (1) at each step.

Step 3

Exam Tip

\(1=\sqrt{1}\) मानने से पूरा क्रम स्पष्ट दिखता है। फिर हर नए चरण में अंदर की संख्या (1) बढ़ती है।

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Mathematics Answer, Explanation and Revision Hints

वर्गमूल सर्पिल में (OA=1) को \(\sqrt{1}\) मानने का मुख्य लाभ क्या है? / What is the main advantage of treating (OA=1) as \(\sqrt{1}\) in a square root spiral?

Correct Answer: A. क्रम \(\sqrt{1},\sqrt{2},\sqrt{3}\) स्पष्ट हो जाता है / The order \(\sqrt{1},\sqrt{2},\sqrt{3}\) becomes clear. Explanation: \(1=\sqrt{1}\) मानने से पूरा क्रम स्पष्ट दिखता है। फिर हर नए चरण में अंदर की संख्या (1) बढ़ती है। / Taking \(1=\sqrt{1}\) makes the whole sequence clear. Then the inner number increases by (1) at each step.

Which concept should I revise for this Mathematics MCQ?

Taking \(1=\sqrt{1}\) makes the whole sequence clear. Then the inner number increases by (1) at each step.

What exam hint can help solve this Mathematics question?

\(1=\sqrt{1}\) मानने से पूरा क्रम स्पष्ट दिखता है। फिर हर नए चरण में अंदर की संख्या (1) बढ़ती है।