अनुक्रम \(88,81,74,67,\ldots\) का सामान्य पद क्या है?

What is the general term of the sequence \(88,81,74,67,\ldots\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. \(a_n=95-7n\)

Step 1

Concept

At (n=1) it gives (88) and at (n=2) it gives (81) so \(a_n=95-7n\). In exams check the first two terms of a decreasing sequence.

Step 2

Why this answer is correct

The correct answer is B. \(a_n=95-7n\). At (n=1) it gives (88) and at (n=2) it gives (81) so \(a_n=95-7n\). In exams check the first two terms of a decreasing sequence.

Step 3

Exam Tip

(n=1) पर (88) और (n=2) पर (81) मिलता है इसलिए \(a_n=95-7n\) है। परीक्षा में घटते अनुक्रम के पहले दो पद जाँचें।

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Mathematics Answer, Explanation and Revision Hints

अनुक्रम \(88,81,74,67,\ldots\) का सामान्य पद क्या है? / What is the general term of the sequence \(88,81,74,67,\ldots\)?

Correct Answer: B. \(a_n=95-7n\). Explanation: (n=1) पर (88) और (n=2) पर (81) मिलता है इसलिए \(a_n=95-7n\) है। परीक्षा में घटते अनुक्रम के पहले दो पद जाँचें। / At (n=1) it gives (88) and at (n=2) it gives (81) so \(a_n=95-7n\). In exams check the first two terms of a decreasing sequence.

Which concept should I revise for this Mathematics MCQ?

At (n=1) it gives (88) and at (n=2) it gives (81) so \(a_n=95-7n\). In exams check the first two terms of a decreasing sequence.

What exam hint can help solve this Mathematics question?

(n=1) पर (88) और (n=2) पर (81) मिलता है इसलिए \(a_n=95-7n\) है। परीक्षा में घटते अनुक्रम के पहले दो पद जाँचें।