अनुक्रम \(4,9,16,25,\ldots\) का सामान्य पद क्या है?

What is the general term of the sequence \(4,9,16,25,\ldots\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

A. (a_n=(n+1)2)

Step 1

Concept

These terms are \(2^2,3^2,4^2,5^2\), so (a_n=(n+1)2). In exams, recognize shifted square numbers.

Step 2

Why this answer is correct

The correct answer is A. (a_n=(n+1)2). These terms are \(2^2,3^2,4^2,5^2\), so (a_n=(n+1)2). In exams, recognize shifted square numbers.

Step 3

Exam Tip

ये पद \(2^2,3^2,4^2,5^2\) हैं, इसलिए (a_n=(n+1)2) है। परीक्षा में वर्ग संख्याओं के स्थानांतरण को पहचानें।

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Mathematics Answer, Explanation and Revision Hints

अनुक्रम \(4,9,16,25,\ldots\) का सामान्य पद क्या है? / What is the general term of the sequence \(4,9,16,25,\ldots\)?

Correct Answer: A. (a_n=(n+1)2). Explanation: ये पद \(2^2,3^2,4^2,5^2\) हैं, इसलिए (a_n=(n+1)2) है। परीक्षा में वर्ग संख्याओं के स्थानांतरण को पहचानें। / These terms are \(2^2,3^2,4^2,5^2\), so (a_n=(n+1)2). In exams, recognize shifted square numbers.

Which concept should I revise for this Mathematics MCQ?

These terms are \(2^2,3^2,4^2,5^2\), so (a_n=(n+1)2). In exams, recognize shifted square numbers.

What exam hint can help solve this Mathematics question?

ये पद \(2^2,3^2,4^2,5^2\) हैं, इसलिए (a_n=(n+1)2) है। परीक्षा में वर्ग संख्याओं के स्थानांतरण को पहचानें।