अनुक्रम \(3,6,12,24,\ldots\) का सामान्य पद क्या है?

What is the general term of the sequence \(3,6,12,24,\ldots\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

D. \(a_n=3\cdot2^{n-1}\)

Step 1

Concept

The first term is (3) and each term is multiplied by (2) so \(a_n=3\cdot2^{n-1}\). In exams check both the first term and ratio.

Step 2

Why this answer is correct

The correct answer is D. \(a_n=3\cdot2^{n-1}\). The first term is (3) and each term is multiplied by (2) so \(a_n=3\cdot2^{n-1}\). In exams check both the first term and ratio.

Step 3

Exam Tip

पहला पद (3) है और हर बार (2) से गुणा हो रहा है इसलिए \(a_n=3\cdot2^{n-1}\) है। परीक्षा में पहले पद और अनुपात दोनों देखें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

अनुक्रम \(3,6,12,24,\ldots\) का सामान्य पद क्या है? / What is the general term of the sequence \(3,6,12,24,\ldots\)?

Correct Answer: D. \(a_n=3\cdot2^{n-1}\). Explanation: पहला पद (3) है और हर बार (2) से गुणा हो रहा है इसलिए \(a_n=3\cdot2^{n-1}\) है। परीक्षा में पहले पद और अनुपात दोनों देखें। / The first term is (3) and each term is multiplied by (2) so \(a_n=3\cdot2^{n-1}\). In exams check both the first term and ratio.

Which concept should I revise for this Mathematics MCQ?

The first term is (3) and each term is multiplied by (2) so \(a_n=3\cdot2^{n-1}\). In exams check both the first term and ratio.

What exam hint can help solve this Mathematics question?

पहला पद (3) है और हर बार (2) से गुणा हो रहा है इसलिए \(a_n=3\cdot2^{n-1}\) है। परीक्षा में पहले पद और अनुपात दोनों देखें।