अनुक्रम \(2,\frac{7}{2},5,\frac{13}{2},\ldots\) का सामान्य पद क्या है?

What is the general term of the sequence \(2,\frac{7}{2},5,\frac{13}{2},\ldots\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

B. \(a_n=\frac{3n+1}{2}\)

Step 1

Concept

\(\frac{3n+1}{2}\) gives \(2,\frac{7}{2},5,\frac{13}{2}\). In exams, match fractional terms using small (n) values.

Step 2

Why this answer is correct

The correct answer is B. \(a_n=\frac{3n+1}{2}\). \(\frac{3n+1}{2}\) gives \(2,\frac{7}{2},5,\frac{13}{2}\). In exams, match fractional terms using small (n) values.

Step 3

Exam Tip

\(\frac{3n+1}{2}\) से \(2,\frac{7}{2},5,\frac{13}{2}\) मिलते हैं। परीक्षा में भिन्न पदों को छोटे (n) मानों से मिलाएँ।

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Mathematics Answer, Explanation and Revision Hints

अनुक्रम \(2,\frac{7}{2},5,\frac{13}{2},\ldots\) का सामान्य पद क्या है? / What is the general term of the sequence \(2,\frac{7}{2},5,\frac{13}{2},\ldots\)?

Correct Answer: B. \(a_n=\frac{3n+1}{2}\). Explanation: \(\frac{3n+1}{2}\) से \(2,\frac{7}{2},5,\frac{13}{2}\) मिलते हैं। परीक्षा में भिन्न पदों को छोटे (n) मानों से मिलाएँ। / \(\frac{3n+1}{2}\) gives \(2,\frac{7}{2},5,\frac{13}{2}\). In exams, match fractional terms using small (n) values.

Which concept should I revise for this Mathematics MCQ?

\(\frac{3n+1}{2}\) gives \(2,\frac{7}{2},5,\frac{13}{2}\). In exams, match fractional terms using small (n) values.

What exam hint can help solve this Mathematics question?

\(\frac{3n+1}{2}\) से \(2,\frac{7}{2},5,\frac{13}{2}\) मिलते हैं। परीक्षा में भिन्न पदों को छोटे (n) मानों से मिलाएँ।