अनुक्रम \(16,25,36,49,\ldots\) का सामान्य पद क्या है?
What is the general term of the sequence \(16,25,36,49,\ldots\)?
Explanation opens after your attempt
B. (a_n=(n+3)2)
Concept
These terms are \(4^2,5^2,6^2,7^2\) so (a_n=(n+3)2). In exams recognize shifted square numbers.
Why this answer is correct
The correct answer is B. (a_n=(n+3)2). These terms are \(4^2,5^2,6^2,7^2\) so (a_n=(n+3)2). In exams recognize shifted square numbers.
Exam Tip
ये पद \(4^2,5^2,6^2,7^2\) हैं इसलिए (a_n=(n+3)2) है। परीक्षा में स्थानांतरित वर्ग संख्याएँ पहचानें।
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