अनुक्रम \(1,5,11,19,\ldots\) का सामान्य पद क्या है?

What is the general term of the sequence \(1,5,11,19,\ldots\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

C. \(a_n=n^2+n-1\)

Step 1

Concept

\(n^2+n-1\) gives (1,5,11,19). In exams, check a quadratic rule when second differences are constant.

Step 2

Why this answer is correct

The correct answer is C. \(a_n=n^2+n-1\). \(n^2+n-1\) gives (1,5,11,19). In exams, check a quadratic rule when second differences are constant.

Step 3

Exam Tip

\(n^2+n-1\) से (1,5,11,19) मिलते हैं। परीक्षा में दूसरे अंतर समान हों तो वर्गीय नियम जाँचें।

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Mathematics Answer, Explanation and Revision Hints

अनुक्रम \(1,5,11,19,\ldots\) का सामान्य पद क्या है? / What is the general term of the sequence \(1,5,11,19,\ldots\)?

Correct Answer: C. \(a_n=n^2+n-1\). Explanation: \(n^2+n-1\) से (1,5,11,19) मिलते हैं। परीक्षा में दूसरे अंतर समान हों तो वर्गीय नियम जाँचें। / \(n^2+n-1\) gives (1,5,11,19). In exams, check a quadratic rule when second differences are constant.

Which concept should I revise for this Mathematics MCQ?

\(n^2+n-1\) gives (1,5,11,19). In exams, check a quadratic rule when second differences are constant.

What exam hint can help solve this Mathematics question?

\(n^2+n-1\) से (1,5,11,19) मिलते हैं। परीक्षा में दूसरे अंतर समान हों तो वर्गीय नियम जाँचें।