गुणोत्तर श्रेणी \(216,72,24,8,\ldots\) का सामान्य पद क्या है?

What is the general term of the geometric progression \(216,72,24,8,\ldots\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. (a_n=216\cdot\left\(\frac{1}{3}\right\)^{n-1})

Step 1

Concept

The first term is (216) and the ratio is \(\frac{1}{3}\), so the correct rule is (216\cdot\left\(\frac{1}{3}\right\)^{n-1}). In exams, write the fractional ratio in a decreasing GP.

Step 2

Why this answer is correct

The correct answer is B. (a_n=216\cdot\left\(\frac{1}{3}\right\)^{n-1}). The first term is (216) and the ratio is \(\frac{1}{3}\), so the correct rule is (216\cdot\left\(\frac{1}{3}\right\)^{n-1}). In exams, write the fractional ratio in a decreasing GP.

Step 3

Exam Tip

पहला पद (216) और अनुपात \(\frac{1}{3}\) है, इसलिए सही नियम (216\cdot\left\(\frac{1}{3}\right\)^{n-1}) है। परीक्षा में घटती GP में भिन्न अनुपात लिखें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

गुणोत्तर श्रेणी \(216,72,24,8,\ldots\) का सामान्य पद क्या है? / What is the general term of the geometric progression \(216,72,24,8,\ldots\)?

Correct Answer: B. (a_n=216\cdot\left\(\frac{1}{3}\right\)^{n-1}). Explanation: पहला पद (216) और अनुपात \(\frac{1}{3}\) है, इसलिए सही नियम (216\cdot\left\(\frac{1}{3}\right\)^{n-1}) है। परीक्षा में घटती GP में भिन्न अनुपात लिखें। / The first term is (216) and the ratio is \(\frac{1}{3}\), so the correct rule is (216\cdot\left\(\frac{1}{3}\right\)^{n-1}). In exams, write the fractional ratio in a decreasing GP.

Which concept should I revise for this Mathematics MCQ?

The first term is (216) and the ratio is \(\frac{1}{3}\), so the correct rule is (216\cdot\left\(\frac{1}{3}\right\)^{n-1}). In exams, write the fractional ratio in a decreasing GP.

What exam hint can help solve this Mathematics question?

पहला पद (216) और अनुपात \(\frac{1}{3}\) है, इसलिए सही नियम (216\cdot\left\(\frac{1}{3}\right\)^{n-1}) है। परीक्षा में घटती GP में भिन्न अनुपात लिखें।