बहुपद (\(x^5+4\)2-\(x^{10}+8x^5\)) की डिग्री क्या है?

What is the degree of (\(x^5+4\)2-\(x^{10}+8x^5\))?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

C. (0)

Step 1

Concept

(\(x^5+4\)2=x^{10}+8x-5+16). After subtraction, (16) remains, whose degree is (0).

Step 2

Why this answer is correct

The correct answer is C. (0). (\(x^5+4\)2=x^{10}+8x-5+16). After subtraction, (16) remains, whose degree is (0).

Step 3

Exam Tip

(\(x^5+4\)2=x^{10}+8x-5+16) होता है। घटाने पर (16) बचता है जिसकी डिग्री (0) है।

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Mathematics Answer, Explanation and Revision Hints

बहुपद (\(x^5+4\)2-\(x^{10}+8x^5\)) की डिग्री क्या है? / What is the degree of (\(x^5+4\)2-\(x^{10}+8x^5\))?

Correct Answer: C. (0). Explanation: (\(x^5+4\)2=x^{10}+8x-5+16) होता है। घटाने पर (16) बचता है जिसकी डिग्री (0) है। / (\(x^5+4\)2=x^{10}+8x-5+16). After subtraction, (16) remains, whose degree is (0).

Which concept should I revise for this Mathematics MCQ?

(\(x^5+4\)2=x^{10}+8x-5+16). After subtraction, (16) remains, whose degree is (0).

What exam hint can help solve this Mathematics question?

(\(x^5+4\)2=x^{10}+8x-5+16) होता है। घटाने पर (16) बचता है जिसकी डिग्री (0) है।