वर्गमूल सर्पिल में \(\sqrt{2}\) से \(\sqrt{5}\) तक पहुँचने का सही क्रम कौन-सा है?

What is the correct order to reach from \(\sqrt{2}\) to \(\sqrt{5}\) in a square root spiral?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

A. \(\sqrt{2}\rightarrow\sqrt{3}\rightarrow\sqrt{4}\rightarrow\sqrt{5}\)

Step 1

Concept

In a square root spiral, hypotenuses are formed successively. In the usual construction, intermediate steps are not skipped.

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{2}\rightarrow\sqrt{3}\rightarrow\sqrt{4}\rightarrow\sqrt{5}\). In a square root spiral, hypotenuses are formed successively. In the usual construction, intermediate steps are not skipped.

Step 3

Exam Tip

वर्गमूल सर्पिल में कर्ण क्रमिक रूप से बनते हैं। सामान्य निर्माण में बीच के चरण छोड़े नहीं जाते।

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Mathematics Answer, Explanation and Revision Hints

वर्गमूल सर्पिल में \(\sqrt{2}\) से \(\sqrt{5}\) तक पहुँचने का सही क्रम कौन-सा है? / What is the correct order to reach from \(\sqrt{2}\) to \(\sqrt{5}\) in a square root spiral?

Correct Answer: A. \(\sqrt{2}\rightarrow\sqrt{3}\rightarrow\sqrt{4}\rightarrow\sqrt{5}\). Explanation: वर्गमूल सर्पिल में कर्ण क्रमिक रूप से बनते हैं। सामान्य निर्माण में बीच के चरण छोड़े नहीं जाते। / In a square root spiral, hypotenuses are formed successively. In the usual construction, intermediate steps are not skipped.

Which concept should I revise for this Mathematics MCQ?

In a square root spiral, hypotenuses are formed successively. In the usual construction, intermediate steps are not skipped.

What exam hint can help solve this Mathematics question?

वर्गमूल सर्पिल में कर्ण क्रमिक रूप से बनते हैं। सामान्य निर्माण में बीच के चरण छोड़े नहीं जाते।