\(x^4-y^4\) का पूर्ण गुणनखंड रूप क्या है?

What is the complete factorised form of \(x^4-y^4\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

B. ((x-y)(x+y)\(x^2+y^2\))सही पूर्ण रूप

Step 1

Concept

(x-4-y-4=\(x^2-y^2\)\(x^2+y^2\)), and \(x^2-y^2\) factors again. In exams check difference of squares twice.

Step 2

Why this answer is correct

The correct answer is B. ((x-y)(x+y)\(x^2+y^2\)) / सही पूर्ण रूप. (x-4-y-4=\(x^2-y^2\)\(x^2+y^2\)), and \(x^2-y^2\) factors again. In exams check difference of squares twice.

Step 3

Exam Tip

(x-4-y-4=\(x^2-y^2\)\(x^2+y^2\)) और \(x^2-y^2\) फिर टूटता है। परीक्षा में दो बार वर्गों का अंतर देखें।

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Mathematics Answer, Explanation and Revision Hints

\(x^4-y^4\) का पूर्ण गुणनखंड रूप क्या है? / What is the complete factorised form of \(x^4-y^4\)?

Correct Answer: B. ((x-y)(x+y)\(x^2+y^2\)) / सही पूर्ण रूप. Explanation: (x-4-y-4=\(x^2-y^2\)\(x^2+y^2\)) और \(x^2-y^2\) फिर टूटता है। परीक्षा में दो बार वर्गों का अंतर देखें। / (x-4-y-4=\(x^2-y^2\)\(x^2+y^2\)), and \(x^2-y^2\) factors again. In exams check difference of squares twice.

Which concept should I revise for this Mathematics MCQ?

(x-4-y-4=\(x^2-y^2\)\(x^2+y^2\)), and \(x^2-y^2\) factors again. In exams check difference of squares twice.

What exam hint can help solve this Mathematics question?

(x-4-y-4=\(x^2-y^2\)\(x^2+y^2\)) और \(x^2-y^2\) फिर टूटता है। परीक्षा में दो बार वर्गों का अंतर देखें।