\(x^4-81\) का पूर्ण गुणनखंड रूप क्या है?

What is the complete factorised form of \(x^4-81\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. ((x-3)(x+3)\(x^2+9\))

Step 1

Concept

First (x-4-81=\(x^2-9\)\(x^2+9\)), then (x-2-9=(x-3)(x+3)). Exam tip: factor further when possible.

Step 2

Why this answer is correct

The correct answer is B. ((x-3)(x+3)\(x^2+9\)). First (x-4-81=\(x^2-9\)\(x^2+9\)), then (x-2-9=(x-3)(x+3)). Exam tip: factor further when possible.

Step 3

Exam Tip

पहले (x-4-81=\(x^2-9\)\(x^2+9\)), फिर (x-2-9=(x-3)(x+3)) होता है। परीक्षा में आगे टूट सकने वाले भाग को फिर तोड़ें।

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\(x^4-81\) का पूर्ण गुणनखंड रूप क्या है? / What is the complete factorised form of \(x^4-81\)?

Correct Answer: B. ((x-3)(x+3)\(x^2+9\)). Explanation: पहले (x-4-81=\(x^2-9\)\(x^2+9\)), फिर (x-2-9=(x-3)(x+3)) होता है। परीक्षा में आगे टूट सकने वाले भाग को फिर तोड़ें। / First (x-4-81=\(x^2-9\)\(x^2+9\)), then (x-2-9=(x-3)(x+3)). Exam tip: factor further when possible.

Which concept should I revise for this Mathematics MCQ?

First (x-4-81=\(x^2-9\)\(x^2+9\)), then (x-2-9=(x-3)(x+3)). Exam tip: factor further when possible.

What exam hint can help solve this Mathematics question?

पहले (x-4-81=\(x^2-9\)\(x^2+9\)), फिर (x-2-9=(x-3)(x+3)) होता है। परीक्षा में आगे टूट सकने वाले भाग को फिर तोड़ें।