समानांतर श्रेढ़ी \(6,14,22,30,\ldots\) के पहले (3) पदों का औसत क्या है?

What is the average of the first (3) terms of the arithmetic progression \(6,14,22,30,\ldots\)?

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Correct Answer

B. (14)

Step 1

Concept

The average of the first three terms is \(\frac{6+14+22}{3}=14\). In an arithmetic progression the average of three consecutive terms is the middle term.

Step 2

Why this answer is correct

The correct answer is B. (14). The average of the first three terms is \(\frac{6+14+22}{3}=14\). In an arithmetic progression the average of three consecutive terms is the middle term.

Step 3

Exam Tip

पहले तीन पदों का औसत \(\frac{6+14+22}{3}=14\) है। समानांतर श्रेढ़ी में तीन क्रमिक पदों का औसत बीच वाला पद होता है।

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समानांतर श्रेढ़ी \(6,14,22,30,\ldots\) के पहले (3) पदों का औसत क्या है? / What is the average of the first (3) terms of the arithmetic progression \(6,14,22,30,\ldots\)?

Correct Answer: B. (14). Explanation: पहले तीन पदों का औसत \(\frac{6+14+22}{3}=14\) है। समानांतर श्रेढ़ी में तीन क्रमिक पदों का औसत बीच वाला पद होता है। / The average of the first three terms is \(\frac{6+14+22}{3}=14\). In an arithmetic progression the average of three consecutive terms is the middle term.

Which concept should I revise for this Mathematics MCQ?

The average of the first three terms is \(\frac{6+14+22}{3}=14\). In an arithmetic progression the average of three consecutive terms is the middle term.

What exam hint can help solve this Mathematics question?

पहले तीन पदों का औसत \(\frac{6+14+22}{3}=14\) है। समानांतर श्रेढ़ी में तीन क्रमिक पदों का औसत बीच वाला पद होता है।