अनुक्रम \(2,12,36,80,150,\ldots\) का सामान्य पद \(a_n=n^3+n^2\) है। \(a_8-a_6\) क्या होगा?
The sequence \(2,12,36,80,150,\ldots\) has general term \(a_n=n^3+n^2\). What will be \(a_8-a_6\)?
Explanation opens after your attempt
C. (336)
Concept
\(a_8=576\) and \(a_6=252\), so the difference is (324), not (336). Recheck cube and square calculations carefully.
Why this answer is correct
The correct answer is C. (336). \(a_8=576\) and \(a_6=252\), so the difference is (324), not (336). Recheck cube and square calculations carefully.
Exam Tip
\(a_8=576\) और \(a_6=252\) इसलिए अंतर (324) नहीं बल्कि (336) है। गणना में घन और वर्ग दोनों ध्यान से निकालें।
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