वर्गमूल सर्पिल में \(\sqrt{255}\) बनाने से ठीक पहले कौन-सा कर्ण होगा?

Just before constructing \(\sqrt{255}\) in a square root spiral, which hypotenuse will be present?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

B. \(\sqrt{254}\)

Step 1

Concept

Adding a (1) unit perpendicular to \(\sqrt{254}\) gives \(\sqrt{255}\). The previous hypotenuse has one less number.

Step 2

Why this answer is correct

The correct answer is B. \(\sqrt{254}\). Adding a (1) unit perpendicular to \(\sqrt{254}\) gives \(\sqrt{255}\). The previous hypotenuse has one less number.

Step 3

Exam Tip

\(\sqrt{254}\) में (1) इकाई लंब जोड़ने पर \(\sqrt{255}\) मिलता है। पिछले कर्ण की संख्या एक कम होती है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

वर्गमूल सर्पिल में \(\sqrt{255}\) बनाने से ठीक पहले कौन-सा कर्ण होगा? / Just before constructing \(\sqrt{255}\) in a square root spiral, which hypotenuse will be present?

Correct Answer: B. \(\sqrt{254}\). Explanation: \(\sqrt{254}\) में (1) इकाई लंब जोड़ने पर \(\sqrt{255}\) मिलता है। पिछले कर्ण की संख्या एक कम होती है। / Adding a (1) unit perpendicular to \(\sqrt{254}\) gives \(\sqrt{255}\). The previous hypotenuse has one less number.

Which concept should I revise for this Mathematics MCQ?

Adding a (1) unit perpendicular to \(\sqrt{254}\) gives \(\sqrt{255}\). The previous hypotenuse has one less number.

What exam hint can help solve this Mathematics question?

\(\sqrt{254}\) में (1) इकाई लंब जोड़ने पर \(\sqrt{255}\) मिलता है। पिछले कर्ण की संख्या एक कम होती है।