वर्गमूल सर्पिल में \(\sqrt{255}\) बनाने से ठीक पहले कौन-सा कर्ण होगा?
Just before constructing \(\sqrt{255}\) in a square root spiral, which hypotenuse will be present?
Explanation opens after your attempt
B. \(\sqrt{254}\)
Concept
Adding a (1) unit perpendicular to \(\sqrt{254}\) gives \(\sqrt{255}\). The previous hypotenuse has one less number.
Why this answer is correct
The correct answer is B. \(\sqrt{254}\). Adding a (1) unit perpendicular to \(\sqrt{254}\) gives \(\sqrt{255}\). The previous hypotenuse has one less number.
Exam Tip
\(\sqrt{254}\) में (1) इकाई लंब जोड़ने पर \(\sqrt{255}\) मिलता है। पिछले कर्ण की संख्या एक कम होती है।
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