वर्गमूल सर्पिल में \(\sqrt{121}\) बनाने से ठीक पहले कौन-सा कर्ण होना चाहिए?

Just before constructing \(\sqrt{121}\) in a square root spiral, which hypotenuse should be present?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. \(\sqrt{120}\)

Step 1

Concept

Adding a (1) unit perpendicular to \(\sqrt{120}\) forms \(\sqrt{121}\). This is the rule of stepwise construction.

Step 2

Why this answer is correct

The correct answer is B. \(\sqrt{120}\). Adding a (1) unit perpendicular to \(\sqrt{120}\) forms \(\sqrt{121}\). This is the rule of stepwise construction.

Step 3

Exam Tip

\(\sqrt{120}\) में (1) इकाई लंब जोड़ने पर \(\sqrt{121}\) बनता है। यह क्रमिक निर्माण का नियम है।

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वर्गमूल सर्पिल में \(\sqrt{121}\) बनाने से ठीक पहले कौन-सा कर्ण होना चाहिए? / Just before constructing \(\sqrt{121}\) in a square root spiral, which hypotenuse should be present?

Correct Answer: B. \(\sqrt{120}\). Explanation: \(\sqrt{120}\) में (1) इकाई लंब जोड़ने पर \(\sqrt{121}\) बनता है। यह क्रमिक निर्माण का नियम है। / Adding a (1) unit perpendicular to \(\sqrt{120}\) forms \(\sqrt{121}\). This is the rule of stepwise construction.

Which concept should I revise for this Mathematics MCQ?

Adding a (1) unit perpendicular to \(\sqrt{120}\) forms \(\sqrt{121}\). This is the rule of stepwise construction.

What exam hint can help solve this Mathematics question?

\(\sqrt{120}\) में (1) इकाई लंब जोड़ने पर \(\sqrt{121}\) बनता है। यह क्रमिक निर्माण का नियम है।