वर्गमूल सर्पिल में \(\sqrt{6}\) की लंबाई बनाने से ठीक पहले कौन-सा कर्ण बना होता है?
Just before constructing length \(\sqrt{6}\) in a square root spiral, which hypotenuse has been constructed?
Explanation opens after your attempt
B. \(\sqrt{5}\)
Concept
Adding a (1) unit perpendicular to \(\sqrt{5}\) gives \(\sqrt{6}\). Look at the previous step.
Why this answer is correct
The correct answer is B. \(\sqrt{5}\). Adding a (1) unit perpendicular to \(\sqrt{5}\) gives \(\sqrt{6}\). Look at the previous step.
Exam Tip
\(\sqrt{5}\) पर (1) इकाई लंब जोड़ने से \(\sqrt{6}\) मिलता है। पिछले चरण को देखें।
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