वर्गमूल सर्पिल में \(\sqrt{6}\) की लंबाई बनाने से ठीक पहले कौन-सा कर्ण बना होता है?

Just before constructing length \(\sqrt{6}\) in a square root spiral, which hypotenuse has been constructed?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. \(\sqrt{5}\)

Step 1

Concept

Adding a (1) unit perpendicular to \(\sqrt{5}\) gives \(\sqrt{6}\). Look at the previous step.

Step 2

Why this answer is correct

The correct answer is B. \(\sqrt{5}\). Adding a (1) unit perpendicular to \(\sqrt{5}\) gives \(\sqrt{6}\). Look at the previous step.

Step 3

Exam Tip

\(\sqrt{5}\) पर (1) इकाई लंब जोड़ने से \(\sqrt{6}\) मिलता है। पिछले चरण को देखें।

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वर्गमूल सर्पिल में \(\sqrt{6}\) की लंबाई बनाने से ठीक पहले कौन-सा कर्ण बना होता है? / Just before constructing length \(\sqrt{6}\) in a square root spiral, which hypotenuse has been constructed?

Correct Answer: B. \(\sqrt{5}\). Explanation: \(\sqrt{5}\) पर (1) इकाई लंब जोड़ने से \(\sqrt{6}\) मिलता है। पिछले चरण को देखें। / Adding a (1) unit perpendicular to \(\sqrt{5}\) gives \(\sqrt{6}\). Look at the previous step.

Which concept should I revise for this Mathematics MCQ?

Adding a (1) unit perpendicular to \(\sqrt{5}\) gives \(\sqrt{6}\). Look at the previous step.

What exam hint can help solve this Mathematics question?

\(\sqrt{5}\) पर (1) इकाई लंब जोड़ने से \(\sqrt{6}\) मिलता है। पिछले चरण को देखें।