किस व्यंजक में \(x^0\) के कारण स्थिर पद बनता है?

In which expression does \(x^0\) form a constant term?

Explanation opens after your attempt
Correct Answer

A. \(6x^0+5x\)

Step 1

Concept

\(x^0=1\) when \(x\neq0\). So \(6x^0\) behaves like the constant term (6).

Step 2

Why this answer is correct

The correct answer is A. \(6x^0+5x\). \(x^0=1\) when \(x\neq0\). So \(6x^0\) behaves like the constant term (6).

Step 3

Exam Tip

\(x^0=1\) माना जाता है जब \(x\neq0\)। इसलिए \(6x^0\) स्थिर पद (6) जैसा है।

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Mathematics Answer, Explanation and Revision Hints

किस व्यंजक में \(x^0\) के कारण स्थिर पद बनता है? / In which expression does \(x^0\) form a constant term?

Correct Answer: A. \(6x^0+5x\). Explanation: \(x^0=1\) माना जाता है जब \(x\neq0\)। इसलिए \(6x^0\) स्थिर पद (6) जैसा है। / \(x^0=1\) when \(x\neq0\). So \(6x^0\) behaves like the constant term (6).

Which concept should I revise for this Mathematics MCQ?

\(x^0=1\) when \(x\neq0\). So \(6x^0\) behaves like the constant term (6).

What exam hint can help solve this Mathematics question?

\(x^0=1\) माना जाता है जब \(x\neq0\)। इसलिए \(6x^0\) स्थिर पद (6) जैसा है।