सर्पिल में यदि \(OP_n=\sqrt{n+1}\) माना जाए, तो \(OP_{12}\) की लंबाई क्या होगी?
In the spiral, if \(OP_n=\sqrt{n+1}\), what is the length of \(OP_{12}\)?
Explanation opens after your attempt
C. \(\sqrt{13}\)
Concept
Putting (n=12) in the formula gives \(OP_{12}=\sqrt{13}\). Pay attention to the difference between the index and the number under the root.
Why this answer is correct
The correct answer is C. \(\sqrt{13}\). Putting (n=12) in the formula gives \(OP_{12}=\sqrt{13}\). Pay attention to the difference between the index and the number under the root.
Exam Tip
सूत्र में (n=12) रखने पर \(OP_{12}=\sqrt{13}\) मिलता है। सूचकांक और वर्गमूल के अंदर की संख्या में अंतर पर ध्यान दें।
Login to save your score, XP, coins and progress.
