अनुक्रम \(1,\frac{1}{4},\frac{1}{9},\frac{1}{16},\ldots\) में पहला पद जो \(\frac{1}{100}\) से छोटा है कौन सा है?
In the sequence \(1,\frac{1}{4},\frac{1}{9},\frac{1}{16},\ldots\), which is the first term less than \(\frac{1}{100}\)?
Explanation opens after your attempt
Correct Answer
B. (11)वाँ(11)th
Concept
\(\frac{1}{10^2}=\frac{1}{100}\) is not smaller, and \(\frac{1}{11^2}<\frac{1}{100}\). So the first term is the (11)th.
Why this answer is correct
The correct answer is B. (11)वाँ / (11)th. \(\frac{1}{10^2}=\frac{1}{100}\) is not smaller, and \(\frac{1}{11^2}<\frac{1}{100}\). So the first term is the (11)th.
Exam Tip
\(\frac{1}{10^2}=\frac{1}{100}\) छोटा नहीं है और \(\frac{1}{11^2}<\frac{1}{100}\) है। इसलिए पहला पद (11)वाँ है।
Login to save your score, XP, coins and progress.