\(\sqrt{2}\) के प्रमाण में किस स्थिति से यह पता चलता है कि माना गया \(\frac{m}{n}\) वास्तव में सरलतम रूप नहीं था?
In the proof of \(\sqrt{2}\), which situation shows that the assumed \(\frac{m}{n}\) was actually not in lowest form?
Explanation opens after your attempt
Correct Answer
A. (m) और (n) दोनों (2) से विभाज्य हैंBoth (m) and (n) are divisible by (2)
Concept
If both are divisible by (2), the fraction can be reduced. This does not happen in lowest form.
Why this answer is correct
The correct answer is A. (m) और (n) दोनों (2) से विभाज्य हैं / Both (m) and (n) are divisible by (2). If both are divisible by (2), the fraction can be reduced. This does not happen in lowest form.
Exam Tip
दोनों (2) से विभाज्य हों तो भिन्न को घटाया जा सकता है। सरलतम रूप में ऐसा नहीं होता।
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