गुणोत्तर श्रेणी \(18,36,72,\ldots\) में \(a_n=2304\) हो, तो (n) क्या है?
In the geometric progression \(18,36,72,\ldots\), if \(a_n=2304\), what is (n)?
Explanation opens after your attempt
Correct Answer
B. (8)
Concept
From \(18\cdot2^{n-1}=2304\), \(2^{n-1}=128=2^7\), so (n=8). In exams, factor first and compare powers.
Why this answer is correct
The correct answer is B. (8). From \(18\cdot2^{n-1}=2304\), \(2^{n-1}=128=2^7\), so (n=8). In exams, factor first and compare powers.
Exam Tip
\(18\cdot2^{n-1}=2304\) से \(2^{n-1}=128=2^7\), इसलिए (n=8) है। परीक्षा में गुणनखंड निकालकर घात तुलना करें।
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