गुणोत्तर श्रेणी \(1024,512,256,128,\ldots\) में (2) कौन-सा पद है?

In the geometric progression \(1024,512,256,128,\ldots\), which term is (2)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

C. दसवाँ पद(10)th term

Step 1

Concept

From (1024\left\(\frac{1}{2}\right\)^{n-1}=2), \(2^{10-(n-1)}=2^1\), so (n=10). In exams, count decreasing powers carefully.

Step 2

Why this answer is correct

The correct answer is C. दसवाँ पद / (10)th term. From (1024\left\(\frac{1}{2}\right\)^{n-1}=2), \(2^{10-(n-1)}=2^1\), so (n=10). In exams, count decreasing powers carefully.

Step 3

Exam Tip

(1024\left\(\frac{1}{2}\right\)^{n-1}=2) से \(2^{10-(n-1)}=2^1\), इसलिए (n=10) है। परीक्षा में घटती घातों को सावधानी से गिनें।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

गुणोत्तर श्रेणी \(1024,512,256,128,\ldots\) में (2) कौन-सा पद है? / In the geometric progression \(1024,512,256,128,\ldots\), which term is (2)?

Correct Answer: C. दसवाँ पद / (10)th term. Explanation: (1024\left\(\frac{1}{2}\right\)^{n-1}=2) से \(2^{10-(n-1)}=2^1\), इसलिए (n=10) है। परीक्षा में घटती घातों को सावधानी से गिनें। / From (1024\left\(\frac{1}{2}\right\)^{n-1}=2), \(2^{10-(n-1)}=2^1\), so (n=10). In exams, count decreasing powers carefully.

Which concept should I revise for this Mathematics MCQ?

From (1024\left\(\frac{1}{2}\right\)^{n-1}=2), \(2^{10-(n-1)}=2^1\), so (n=10). In exams, count decreasing powers carefully.

What exam hint can help solve this Mathematics question?

(1024\left\(\frac{1}{2}\right\)^{n-1}=2) से \(2^{10-(n-1)}=2^1\), इसलिए (n=10) है। परीक्षा में घटती घातों को सावधानी से गिनें।