समांतर श्रेणी \(8,14,20,\ldots\) में (80) से पहले आने वाला अंतिम पद कौन-सा है?

In the arithmetic progression \(8,14,20,\ldots\), what is the last term before (80)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

C. (74)

Step 1

Concept

The general term is \(a_n=6n+2\), and the greatest term below (80) is (74). In boundary questions, check nearby terms.

Step 2

Why this answer is correct

The correct answer is C. (74). The general term is \(a_n=6n+2\), and the greatest term below (80) is (74). In boundary questions, check nearby terms.

Step 3

Exam Tip

सामान्य पद \(a_n=6n+2\) है और (80) से छोटा सबसे बड़ा पद (74) है। सीमा वाले प्रश्न में नजदीकी पद जांचें।

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Mathematics Answer, Explanation and Revision Hints

समांतर श्रेणी \(8,14,20,\ldots\) में (80) से पहले आने वाला अंतिम पद कौन-सा है? / In the arithmetic progression \(8,14,20,\ldots\), what is the last term before (80)?

Correct Answer: C. (74). Explanation: सामान्य पद \(a_n=6n+2\) है और (80) से छोटा सबसे बड़ा पद (74) है। सीमा वाले प्रश्न में नजदीकी पद जांचें। / The general term is \(a_n=6n+2\), and the greatest term below (80) is (74). In boundary questions, check nearby terms.

Which concept should I revise for this Mathematics MCQ?

The general term is \(a_n=6n+2\), and the greatest term below (80) is (74). In boundary questions, check nearby terms.

What exam hint can help solve this Mathematics question?

सामान्य पद \(a_n=6n+2\) है और (80) से छोटा सबसे बड़ा पद (74) है। सीमा वाले प्रश्न में नजदीकी पद जांचें।