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In an arithmetic sequence, (a_5=29) and (a_{11}=83). What is the value of (a_{15})?
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Answer and explanation
Correct answer: (119)
The increase over six gaps is (54), so (d=9), hence (a_{15}=83+4(9)=119). Extend the terms using the common difference.
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What is the correct answer to this question?
(119)
Why is this the correct answer?
The increase over six gaps is (54), so (d=9), hence (a_{15}=83+4(9)=119). Extend the terms using the common difference.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Explicit or general rule.
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