किस गुणोत्तर श्रेणी में \(a_3=80\) और \(a_6=5120\) है। यदि (r) धनात्मक है, तो \(a_1\) क्या है?

In a geometric progression \(a_3=80\) and \(a_6=5120\). If (r) is positive, what is \(a_1\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. (5)

Step 1

Concept

\(\frac{5120}{80}=64=r^3\), so (r=4) and \(a_1=\frac{80}{4^2}=5\). In exams, find (r) first and then the first term.

Step 2

Why this answer is correct

The correct answer is B. (5). \(\frac{5120}{80}=64=r^3\), so (r=4) and \(a_1=\frac{80}{4^2}=5\). In exams, find (r) first and then the first term.

Step 3

Exam Tip

\(\frac{5120}{80}=64=r^3\) से (r=4) और \(a_1=\frac{80}{4^2}=5\) है। परीक्षा में पहले (r) निकालें फिर पहला पद।

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किस गुणोत्तर श्रेणी में \(a_3=80\) और \(a_6=5120\) है। यदि (r) धनात्मक है, तो \(a_1\) क्या है? / In a geometric progression \(a_3=80\) and \(a_6=5120\). If (r) is positive, what is \(a_1\)?

Correct Answer: B. (5). Explanation: \(\frac{5120}{80}=64=r^3\) से (r=4) और \(a_1=\frac{80}{4^2}=5\) है। परीक्षा में पहले (r) निकालें फिर पहला पद। / \(\frac{5120}{80}=64=r^3\), so (r=4) and \(a_1=\frac{80}{4^2}=5\). In exams, find (r) first and then the first term.

Which concept should I revise for this Mathematics MCQ?

\(\frac{5120}{80}=64=r^3\), so (r=4) and \(a_1=\frac{80}{4^2}=5\). In exams, find (r) first and then the first term.

What exam hint can help solve this Mathematics question?

\(\frac{5120}{80}=64=r^3\) से (r=4) और \(a_1=\frac{80}{4^2}=5\) है। परीक्षा में पहले (r) निकालें फिर पहला पद।