यदि \(z=\sqrt{11}-\sqrt{7}\) है, तो \(z^2\) का मान कौन-सा है?

If \(z=\sqrt{11}-\sqrt{7}\), which is the value of \(z^2\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(18-2\sqrt{77}\)

Step 1

Concept

(\(\sqrt{11}-\sqrt{7}\)2=11+7-2\sqrt{77}). The middle term stays negative.

Step 2

Why this answer is correct

The correct answer is A. \(18-2\sqrt{77}\). (\(\sqrt{11}-\sqrt{7}\)2=11+7-2\sqrt{77}). The middle term stays negative.

Step 3

Exam Tip

(\(\sqrt{11}-\sqrt{7}\)2=11+7-2\sqrt{77}) है। मध्य पद का चिन्ह ऋणात्मक रहेगा।

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Mathematics Answer, Explanation and Revision Hints

यदि \(z=\sqrt{11}-\sqrt{7}\) है, तो \(z^2\) का मान कौन-सा है? / If \(z=\sqrt{11}-\sqrt{7}\), which is the value of \(z^2\)?

Correct Answer: A. \(18-2\sqrt{77}\). Explanation: (\(\sqrt{11}-\sqrt{7}\)2=11+7-2\sqrt{77}) है। मध्य पद का चिन्ह ऋणात्मक रहेगा। / (\(\sqrt{11}-\sqrt{7}\)2=11+7-2\sqrt{77}). The middle term stays negative.

Which concept should I revise for this Mathematics MCQ?

(\(\sqrt{11}-\sqrt{7}\)2=11+7-2\sqrt{77}). The middle term stays negative.

What exam hint can help solve this Mathematics question?

(\(\sqrt{11}-\sqrt{7}\)2=11+7-2\sqrt{77}) है। मध्य पद का चिन्ह ऋणात्मक रहेगा।