यदि \(y=\sqrt{12}+\sqrt{27}\) है तो \(y^2\) का मान क्या है?
If \(y=\sqrt{12}+\sqrt{27}\), what is the value of \(y^2\)?
Explanation opens after your attempt
Correct Answer
B. (75)
Concept
\(\sqrt{12}=2\sqrt{3}\) and \(\sqrt{27}=3\sqrt{3}\), so \(y=5\sqrt{3}\). Its square is (75).
Why this answer is correct
The correct answer is B. (75). \(\sqrt{12}=2\sqrt{3}\) and \(\sqrt{27}=3\sqrt{3}\), so \(y=5\sqrt{3}\). Its square is (75).
Exam Tip
\(\sqrt{12}=2\sqrt{3}\) और \(\sqrt{27}=3\sqrt{3}\), इसलिए \(y=5\sqrt{3}\) है। इसका वर्ग (75) है।
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