यदि \(x=\sqrt{5}+\sqrt{3}\) है, तो \(x^2-8\) का मान क्या है?
If \(x=\sqrt{5}+\sqrt{3}\), what is the value of \(x^2-8\)?
Explanation opens after your attempt
A. \(2\sqrt{15}\)
Concept
\(x^2=5+3+2\sqrt{15}=8+2\sqrt{15}\). Therefore \(x^2-8=2\sqrt{15}\).
Why this answer is correct
The correct answer is A. \(2\sqrt{15}\). \(x^2=5+3+2\sqrt{15}=8+2\sqrt{15}\). Therefore \(x^2-8=2\sqrt{15}\).
Exam Tip
\(x^2=5+3+2\sqrt{15}=8+2\sqrt{15}\) है। इसलिए \(x^2-8=2\sqrt{15}\) है।
Login to save your score, XP, coins and progress.
