यदि \(x=\sqrt{5}+\sqrt{3}\) है, तो \(x^2-8\) का मान क्या है?

If \(x=\sqrt{5}+\sqrt{3}\), what is the value of \(x^2-8\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(2\sqrt{15}\)

Step 1

Concept

\(x^2=5+3+2\sqrt{15}=8+2\sqrt{15}\). Therefore \(x^2-8=2\sqrt{15}\).

Step 2

Why this answer is correct

The correct answer is A. \(2\sqrt{15}\). \(x^2=5+3+2\sqrt{15}=8+2\sqrt{15}\). Therefore \(x^2-8=2\sqrt{15}\).

Step 3

Exam Tip

\(x^2=5+3+2\sqrt{15}=8+2\sqrt{15}\) है। इसलिए \(x^2-8=2\sqrt{15}\) है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x=\sqrt{5}+\sqrt{3}\) है, तो \(x^2-8\) का मान क्या है? / If \(x=\sqrt{5}+\sqrt{3}\), what is the value of \(x^2-8\)?

Correct Answer: A. \(2\sqrt{15}\). Explanation: \(x^2=5+3+2\sqrt{15}=8+2\sqrt{15}\) है। इसलिए \(x^2-8=2\sqrt{15}\) है। / \(x^2=5+3+2\sqrt{15}=8+2\sqrt{15}\). Therefore \(x^2-8=2\sqrt{15}\).

Which concept should I revise for this Mathematics MCQ?

\(x^2=5+3+2\sqrt{15}=8+2\sqrt{15}\). Therefore \(x^2-8=2\sqrt{15}\).

What exam hint can help solve this Mathematics question?

\(x^2=5+3+2\sqrt{15}=8+2\sqrt{15}\) है। इसलिए \(x^2-8=2\sqrt{15}\) है।