यदि \(x=\sqrt{17}+\sqrt{6}\) है तो \(x^2-23\) का मान क्या है?
If \(x=\sqrt{17}+\sqrt{6}\), what is the value of \(x^2-23\)?
Explanation opens after your attempt
Correct Answer
C. \(2\sqrt{102}\)
Concept
\(x^2=17+6+2\sqrt{102}=23+2\sqrt{102}\). So \(x^2-23=2\sqrt{102}\).
Why this answer is correct
The correct answer is C. \(2\sqrt{102}\). \(x^2=17+6+2\sqrt{102}=23+2\sqrt{102}\). So \(x^2-23=2\sqrt{102}\).
Exam Tip
\(x^2=17+6+2\sqrt{102}=23+2\sqrt{102}\) है। इसलिए \(x^2-23=2\sqrt{102}\) है।
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