यदि \(x=\sqrt{17+\sqrt{13}}\) है तो \(x^2-17\) का मान क्या है?

If \(x=\sqrt{17+\sqrt{13}}\), what is the value of \(x^2-17\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(\sqrt{13}\)

Step 1

Concept

\(x^2=17+\sqrt{13}\). Therefore \(x^2-17=\sqrt{13}\).

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{13}\). \(x^2=17+\sqrt{13}\). Therefore \(x^2-17=\sqrt{13}\).

Step 3

Exam Tip

\(x^2=17+\sqrt{13}\) है। इसलिए \(x^2-17=\sqrt{13}\) होगा।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x=\sqrt{17+\sqrt{13}}\) है तो \(x^2-17\) का मान क्या है? / If \(x=\sqrt{17+\sqrt{13}}\), what is the value of \(x^2-17\)?

Correct Answer: A. \(\sqrt{13}\). Explanation: \(x^2=17+\sqrt{13}\) है। इसलिए \(x^2-17=\sqrt{13}\) होगा। / \(x^2=17+\sqrt{13}\). Therefore \(x^2-17=\sqrt{13}\).

Which concept should I revise for this Mathematics MCQ?

\(x^2=17+\sqrt{13}\). Therefore \(x^2-17=\sqrt{13}\).

What exam hint can help solve this Mathematics question?

\(x^2=17+\sqrt{13}\) है। इसलिए \(x^2-17=\sqrt{13}\) होगा।