यदि \(x=\sqrt{17+\sqrt{13}}\) है तो \(x^2-17\) का मान क्या है?
If \(x=\sqrt{17+\sqrt{13}}\), what is the value of \(x^2-17\)?
Explanation opens after your attempt
A. \(\sqrt{13}\)
Concept
\(x^2=17+\sqrt{13}\). Therefore \(x^2-17=\sqrt{13}\).
Why this answer is correct
The correct answer is A. \(\sqrt{13}\). \(x^2=17+\sqrt{13}\). Therefore \(x^2-17=\sqrt{13}\).
Exam Tip
\(x^2=17+\sqrt{13}\) है। इसलिए \(x^2-17=\sqrt{13}\) होगा।
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