यदि \(x=\sqrt{14}+\sqrt{6}\) है तो \(x^2-20\) का मान क्या है?
If \(x=\sqrt{14}+\sqrt{6}\), what is the value of \(x^2-20\)?
Explanation opens after your attempt
Correct Answer
B. \(2\sqrt{84}\)
Concept
\(x^2=14+6+2\sqrt{84}=20+2\sqrt{84}\). So \(x^2-20=2\sqrt{84}\).
Why this answer is correct
The correct answer is B. \(2\sqrt{84}\). \(x^2=14+6+2\sqrt{84}=20+2\sqrt{84}\). So \(x^2-20=2\sqrt{84}\).
Exam Tip
\(x^2=14+6+2\sqrt{84}=20+2\sqrt{84}\) है। इसलिए \(x^2-20=2\sqrt{84}\) है।
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