यदि \(x=\sqrt{12+\sqrt{11}}\) है तो \(x^2-12\) का मान क्या है?
If \(x=\sqrt{12+\sqrt{11}}\), what is the value of \(x^2-12\)?
Explanation opens after your attempt
Correct Answer
A. \(\sqrt{11}\)
Concept
\(x^2=12+\sqrt{11}\). Therefore \(x^2-12=\sqrt{11}\).
Why this answer is correct
The correct answer is A. \(\sqrt{11}\). \(x^2=12+\sqrt{11}\). Therefore \(x^2-12=\sqrt{11}\).
Exam Tip
\(x^2=12+\sqrt{11}\) है। इसलिए \(x^2-12=\sqrt{11}\) होगा।
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