यदि \(x=\sqrt{11}+\sqrt{3}\) है तो \(x^2-14\) का मान क्या है?
If \(x=\sqrt{11}+\sqrt{3}\), what is the value of \(x^2-14\)?
Explanation opens after your attempt
Correct Answer
A. \(2\sqrt{33}\)
Concept
\(x^2=11+3+2\sqrt{33}=14+2\sqrt{33}\). Therefore \(x^2-14=2\sqrt{33}\).
Why this answer is correct
The correct answer is A. \(2\sqrt{33}\). \(x^2=11+3+2\sqrt{33}=14+2\sqrt{33}\). Therefore \(x^2-14=2\sqrt{33}\).
Exam Tip
\(x^2=11+3+2\sqrt{33}=14+2\sqrt{33}\) है। इसलिए \(x^2-14=2\sqrt{33}\) है।
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