यदि \(x=5+\sqrt{26}\) है तो \(x^2-10x\) का मान क्या है?
If \(x=5+\sqrt{26}\), what is the value of \(x^2-10x\)?
Explanation opens after your attempt
A. (1)
Concept
\(x^2=51+10\sqrt{26}\) and \(10x=50+10\sqrt{26}\). Subtracting gives (1).
Why this answer is correct
The correct answer is A. (1). \(x^2=51+10\sqrt{26}\) and \(10x=50+10\sqrt{26}\). Subtracting gives (1).
Exam Tip
\(x^2=51+10\sqrt{26}\) और \(10x=50+10\sqrt{26}\) है। घटाने पर (1) मिलता है।
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