यदि \(x=5+\sqrt{26}\) है तो \(x^2-10x\) का मान क्या है?

If \(x=5+\sqrt{26}\), what is the value of \(x^2-10x\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. (1)

Step 1

Concept

\(x^2=51+10\sqrt{26}\) and \(10x=50+10\sqrt{26}\). Subtracting gives (1).

Step 2

Why this answer is correct

The correct answer is A. (1). \(x^2=51+10\sqrt{26}\) and \(10x=50+10\sqrt{26}\). Subtracting gives (1).

Step 3

Exam Tip

\(x^2=51+10\sqrt{26}\) और \(10x=50+10\sqrt{26}\) है। घटाने पर (1) मिलता है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x=5+\sqrt{26}\) है तो \(x^2-10x\) का मान क्या है? / If \(x=5+\sqrt{26}\), what is the value of \(x^2-10x\)?

Correct Answer: A. (1). Explanation: \(x^2=51+10\sqrt{26}\) और \(10x=50+10\sqrt{26}\) है। घटाने पर (1) मिलता है। / \(x^2=51+10\sqrt{26}\) and \(10x=50+10\sqrt{26}\). Subtracting gives (1).

Which concept should I revise for this Mathematics MCQ?

\(x^2=51+10\sqrt{26}\) and \(10x=50+10\sqrt{26}\). Subtracting gives (1).

What exam hint can help solve this Mathematics question?

\(x^2=51+10\sqrt{26}\) और \(10x=50+10\sqrt{26}\) है। घटाने पर (1) मिलता है।