यदि \(x=3+\sqrt{10}\) है तो \(x^2-6x\) का मान क्या है?
If \(x=3+\sqrt{10}\), what is the value of \(x^2-6x\)?
Explanation opens after your attempt
A. (1)
Concept
\(x^2=19+6\sqrt{10}\) and \(6x=18+6\sqrt{10}\). Subtracting gives (1).
Why this answer is correct
The correct answer is A. (1). \(x^2=19+6\sqrt{10}\) and \(6x=18+6\sqrt{10}\). Subtracting gives (1).
Exam Tip
\(x^2=19+6\sqrt{10}\) और \(6x=18+6\sqrt{10}\) है। घटाने पर (1) मिलता है।
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