यदि \(w=\sqrt{15}+\sqrt{11}\) है तो \(w^2-26\) का मान क्या है?
If \(w=\sqrt{15}+\sqrt{11}\), what is the value of \(w^2-26\)?
Explanation opens after your attempt
Correct Answer
B. \(2\sqrt{165}\)
Concept
\(w^2=15+11+2\sqrt{165}=26+2\sqrt{165}\). So \(w^2-26=2\sqrt{165}\).
Why this answer is correct
The correct answer is B. \(2\sqrt{165}\). \(w^2=15+11+2\sqrt{165}=26+2\sqrt{165}\). So \(w^2-26=2\sqrt{165}\).
Exam Tip
\(w^2=15+11+2\sqrt{165}=26+2\sqrt{165}\) है। इसलिए \(w^2-26=2\sqrt{165}\) है।
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