यदि समानांतर श्रेढ़ी के लगातार तीन पद (x-2), (x+3), (2x-1) हैं, तो (x) का मान क्या है?
If three consecutive terms of an arithmetic progression are (x-2), (x+3), (2x-1), what is the value of (x)?
Explanation opens after your attempt
D. (7)
Concept
In an arithmetic progression, (2(x+3)=(x-2)+(2x-1)), which gives (x=9). The middle term is the average of the two adjacent terms.
Why this answer is correct
The correct answer is D. (7). In an arithmetic progression, (2(x+3)=(x-2)+(2x-1)), which gives (x=9). The middle term is the average of the two adjacent terms.
Exam Tip
समानांतर श्रेढ़ी में (2(x+3)=(x-2)+(2x-1)), इससे (x=9) मिलता है। बीच का पद दो बराबर हिस्सों में होता है।
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