यदि समानांतर श्रेढ़ी के लगातार तीन पद (x-2), (x+3), (2x-1) हैं, तो (x) का मान क्या है?

If three consecutive terms of an arithmetic progression are (x-2), (x+3), (2x-1), what is the value of (x)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

D. (7)

Step 1

Concept

In an arithmetic progression, (2(x+3)=(x-2)+(2x-1)), which gives (x=9). The middle term is the average of the two adjacent terms.

Step 2

Why this answer is correct

The correct answer is D. (7). In an arithmetic progression, (2(x+3)=(x-2)+(2x-1)), which gives (x=9). The middle term is the average of the two adjacent terms.

Step 3

Exam Tip

समानांतर श्रेढ़ी में (2(x+3)=(x-2)+(2x-1)), इससे (x=9) मिलता है। बीच का पद दो बराबर हिस्सों में होता है।

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Mathematics Answer, Explanation and Revision Hints

यदि समानांतर श्रेढ़ी के लगातार तीन पद (x-2), (x+3), (2x-1) हैं, तो (x) का मान क्या है? / If three consecutive terms of an arithmetic progression are (x-2), (x+3), (2x-1), what is the value of (x)?

Correct Answer: D. (7). Explanation: समानांतर श्रेढ़ी में (2(x+3)=(x-2)+(2x-1)), इससे (x=9) मिलता है। बीच का पद दो बराबर हिस्सों में होता है। / In an arithmetic progression, (2(x+3)=(x-2)+(2x-1)), which gives (x=9). The middle term is the average of the two adjacent terms.

Which concept should I revise for this Mathematics MCQ?

In an arithmetic progression, (2(x+3)=(x-2)+(2x-1)), which gives (x=9). The middle term is the average of the two adjacent terms.

What exam hint can help solve this Mathematics question?

समानांतर श्रेढ़ी में (2(x+3)=(x-2)+(2x-1)), इससे (x=9) मिलता है। बीच का पद दो बराबर हिस्सों में होता है।